1/9q^2-25=0

Solution for 1/9q^2-25=0 equation:

1/9q^2-25=0


Domain of the equation: 9q^2!=0

q^2!=0/9

q^2!=√0

q!=0

q∈R


We multiply all the terms by the denominator


-25*9q^2+1=0

Wy multiply elements

-225q^2+1=0

a = -225; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-225)·1
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*-225}=\frac{-30}{-450}
=1/15
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*-225}=\frac{30}{-450}
=-1/15
$